Citazione:
Originalmente inviato da moonwalkerfj  Ho trovato questa descrizione:
Dropout voltage typically 0.5V @IO = 1A Output current in excess of 1A Output voltage trimmed before assembly Reverse battery protection Internal short circuit current limit Mirror image insertion protection P + Product Enhancement tested Description The LM2940/LM2940C positive voltage regulator features the ability to source 1A of output current with a dropout voltage of typically 0.5V and a maximum of 1V over the entire temperature range. Furthermore, a quiescent current reduction circuit has been included which reduces the ground current when the differential between the input voltage and the output voltage exceeds approximately 3V. The quiescent current with 1A of output current and an input-output differential of 5V is therefore only 30 mA. Higher quiescent currents only exist when the regulator is in the dropout mode (VIN − VOUT ≤ 3V).
Designed also for vehicular applications, the LM2940/LM2940C and all regulated circuitry are protected from reverse battery installations or 2-battery jumps. During line transients, such as load dump when the input voltage can momentarily exceed the specified maximum operating voltage, the regulator will automatically shut down to protect both the internal circuits and the load. The LM2940/LM2940C cannot be harmed by temporary mirror-image insertion. Familiar regulator features such as short circuit and thermal overload protection are also provided.
Perdonami ma io non ne capisco un'H, mi devo preoccupare per quanto ho evidenziato in rosso?
Qui la scheda completa: http://www.national.com/ds/LM/LM2940.pdf
Grazie
Simone |
Io continuo ad esere più preoccupato per le parti evidenziate in verde.......
(quella in rosso è una protezione utile durante l'accensione del motore sulle automobili ....) ......
Lo so che è una mia fissa ........ma 1A mi sembra poco ....troppo poco.....